fix(订单服务): 修复关联订单列表去重逻辑并优化查询结果

确保关联订单列表中的条目不会重复，通过使用Set来跟踪已处理的外部ID
移除不必要的orders数组填充，简化返回数据结构

src/service/order.service.ts

@@ -1330,10 +1330,21 @@ export class OrderService {
     let relatedList: any[] = [];
     try {
       const related = await this.getRelatedByOrder(id);
-      relatedList = [
-        ...(Array.isArray(related?.subscriptions) ? related.subscriptions : []),
-        ...(Array.isArray(related?.orders) ? related.orders : []),
-      ];
+      const subs = Array.isArray(related?.subscriptions) ? related.subscriptions : [];
+      const ords = Array.isArray(related?.orders) ? related.orders : [];
+      const seen = new Set<string>();
+      const merge = [...subs, ...ords];
+      for (const it of merge) {
+        const key = it?.externalSubscriptionId
+          ? `sub:${it.externalSubscriptionId}`
+          : it?.externalOrderId
+          ? `ord:${it.externalOrderId}`
+          : `id:${it?.id}`;
+        if (!seen.has(key)) {
+          seen.add(key);
+          relatedList.push(it);
+        }
+      }
     } catch (error) {
       // 关联查询失败不影响详情返回
     }
@@ -1360,15 +1371,10 @@ export class OrderService {
       WHERE s.siteId = ? AND s.parent_id = ?
     `;
     const subscriptions = await this.orderModel.query(subSql, [siteId, order.externalOrderId]);
-
-
-    const allOrdersMap = new Map<number, any>();
-    subscriptions.forEach(o => allOrdersMap.set(o.id, o));
-
     return {
       order,
       subscriptions,
-      orders: Array.from(allOrdersMap.values()),
+      orders: [],
     };
   }